A 3-phase induction motor is operating at slip s. If two supply leads are interchanged, the slip at that instant will be:


A) 2 − s
B) 2 + s
C) 1 + s
D) 1 − s


✅ Answer: A) 2 − s


🧠 Detailed Solution:

◆ Step 1: Slip Formula

s = (Ns − Nr) / Ns

◆ Step 2: Before Interchanging Leads

Rotor rotates in same direction as stator field.
Slip: s = (Ns − Nr) / Ns

◆ Step 3: After Interchanging Two Phases

→ Phase sequence reverses
→ Rotating magnetic field reverses direction
→ Rotor continues in same direction due to inertia

◆ Step 4: Relative Speed

Relative speed = Ns + Nr

◆ Step 5: New Slip

s' = (Ns + Nr) / Ns

Substitute Nr = Ns(1 − s):

s' = (Ns + Ns(1 − s)) / Ns
s' = 1 + (1 − s) = 2 − s


❌ Why Other Options Are Incorrect

B) 2 + s → Incorrect formula
C) 1 + s → Incomplete expression
D) 1 − s → Wrong interpretation


🔑 Key Points

◆ Interchanging two phases reverses RMF direction
◆ Rotor continues due to inertia
◆ Relative speed becomes (Ns + Nr)
◆ Slip becomes greater than 1 (plugging condition)


🎯 Final Conclusion

Slip after reversing supply leads = 2 − s
Motor enters plugging (braking) condition

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