The frequency of rotor emf of an 8-pole induction motor is 2 Hz. If the supply frequency is 50 Hz, then the motor speed is:


A) 1,500 rpm
B) 750 rpm
C) 375 rpm
D) 720 rpm

✅ Answer:
D) 720 rpm

🧠 Detailed Solution

🔹 1. Given Data:
Supply frequency → f = 50 Hz
Rotor frequency → fr = 2 Hz
Number of poles → P = 8


🔹 2. Calculate Synchronous Speed (Ns):

Ns = (120 × f) / P

Ns = (120 × 50) / 8 = 750 rpm


🔹 3. Calculate Slip (s):

fr = s × f

s = fr / f = 2 / 50 = 0.04

👉 Slip = 4%


🔹 4. Calculate Motor Speed (N):

N = Ns (1 − s)

N = 750 × (1 − 0.04) = 750 × 0.96 = 720 rpm


❌ Why Other Options Are Wrong

A) 1500 rpm ❌ → Corresponds to 4-pole motor, not 8-pole
B) 750 rpm ❌ → This is synchronous speed, not actual speed
C) 375 rpm ❌ → Incorrect calculation


📌 Key Points

• Rotor frequency = Slip × Supply frequency
• Slip = Rotor frequency / Supply frequency
• Actual speed is always less than synchronous speed
• Higher slip → Lower speed


🎯 Final Conclusion

✔ Motor speed = 720 rpm
✔ Correct Option → D

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