With the increase in temperature, the speed of a DC shunt motor __________?

A) Decreases
B) Increases
C) Remains same
D) None of the above

✅ Answer: B) Increases

💡 Detailed Explanation

In a DC shunt motor, the field winding is connected across the supply voltage. When the temperature of the motor increases, the resistance of the copper field winding also increases.

The resistance of a winding changes with temperature according to:

Rₜ = R₀ [1 + α(T − T₀)]

Where:

  • Rₜ = Resistance at temperature T

  • R₀ = Resistance at reference temperature T₀

  • α = Temperature coefficient of resistance

  • T = Final temperature

  • T₀ = Initial temperature

Therefore:

Temperature ↑ → Field resistance Rf ↑


🔹 Step 1: Effect on Field Current

The field current of a DC shunt motor is:

If = V / Rf

Since the supply voltage V is approximately constant, an increase in field resistance causes the field current to decrease.

Therefore:

Rf ↑ → If ↓


🔹 Step 2: Effect on Magnetic Flux

For a DC shunt motor, the magnetic flux is approximately proportional to the field current, particularly before magnetic saturation.

Φ ∝ If

Therefore:

If ↓ → Φ ↓

So, when the motor temperature increases, the field flux tends to decrease.


🔹 Step 3: Effect on Motor Speed

The back EMF of a DC motor is:

Eb = V − IaRa

The speed equation of a DC motor is approximately:

N ∝ Eb / Φ

or

N = K × Eb / Φ

where:

  • N = Motor speed

  • Eb = Back EMF

  • Φ = Magnetic flux

  • K = Motor constant

When the field flux decreases, the speed of the motor tends to increase.

Therefore:

Temperature ↑ → Rf ↑ → If ↓ → Φ ↓ → N ↑

Hence, the correct answer is:

✅ B) Increases


🔢 Numerical Example

Consider a DC shunt motor operating from a 220 V supply.

Initially, the field resistance is:

Rf₁ = 220 Ω

Therefore, the initial field current is:

If₁ = V / Rf₁

If₁ = 220 / 220

If₁ = 1 A

Now suppose the motor temperature increases and the field resistance becomes:

Rf₂ = 242 Ω

The new field current will be:

If₂ = V / Rf₂

If₂ = 220 / 242

If₂ ≈ 0.909 A

Thus:

Field resistance ↑ → Field current ↓

Since the field current decreases, the magnetic flux also decreases.

If ↓ → Φ ↓

Since:

N ∝ Eb / Φ

the motor speed tends to increase.


⚠️ Important Note

The armature resistance also increases when the motor temperature rises. This increases the armature voltage drop:

IaRa

and therefore tends to reduce the back EMF.

However, in this standard MCQ, the important effect being considered is the increase in shunt-field resistance, which reduces field current and flux. Hence, the expected answer is "Increases."


📌 Remember Points

ConditionEffect
🌡️ Temperature increases↑
🔌 Field resistance Rf↑
⚡ Field current If↓
🧲 Field flux Φ↓
⚙️ DC shunt motor speed N↑

🔥 Exam Shortcut

Temperature ↑ → Rf ↑ → If ↓ → Φ ↓ → Speed ↑

✅ Final Answer

B) Increases

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